gofastman Posted December 17, 2015 Author Report Share Posted December 17, 2015 Hi folks, first post here! This isn't necessarily related to the DNA200, but when calculating Watt/hour capacity for the power supply, do you use the batterie's nominal voltage (3.7) or its maximum voltage (4.2)? Thanks! Link to comment Share on other sites More sharing options...
VapingBad Posted December 17, 2015 Report Share Posted December 17, 2015 The nominal battery voltage. Link to comment Share on other sites More sharing options...
gofastman Posted December 17, 2015 Author Report Share Posted December 17, 2015 Thanks! I assume nominal mAh capacity is used also? Link to comment Share on other sites More sharing options...
VapingBad Posted December 18, 2015 Report Share Posted December 18, 2015 Wh = mAh x nominal_voltage / 100011.1 V (3 cells in series)2000 mAh (per cell)=11.1 x 2000 /1000 = 22.2 Whor3.7 V (single cell)6000 mAh (3 x 2000 mAh cells)=3.7 x 6000 / 1000 = 22.2 WhSo series and parallel come out the same Wh. Link to comment Share on other sites More sharing options...
gofastman Posted December 18, 2015 Author Report Share Posted December 18, 2015 I'm using 3 25Rs, nominal capacity is 2500mAh. Capacity in high drain conditions is significantly less. Should I calculate it as 2500, or try to figure out mAh capacity under the conditions they will be used with this device? Link to comment Share on other sites More sharing options...
VapingBad Posted December 18, 2015 Report Share Posted December 18, 2015 In series so 11.1 V x 2500 mAh, but 3.7 V x 3 x 2500 mAh gives the same answer of 27.75 Wh.(IIRC the specs on 25Rs have nominal A 3.6 V, which would give 27 Wh) Link to comment Share on other sites More sharing options...
gofastman Posted December 18, 2015 Author Report Share Posted December 18, 2015 Oh yeah, duh, far less current draw on each cell (vs. a single cell mech) because of the higher voltage. Link to comment Share on other sites More sharing options...
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